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[打法交流] 百家乐连赢概率和连赢策略
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1#
  很多玩家都在苦苦追寻百家乐的连赢玩法,但是对于连赢的认识并不深入。其实百家乐连赢概率和连赢策略是相通,只要摸清了游戏特点,才能找到制胜方法。# i' A4 f4 P# }
  一般来说,
" L+ D, w0 p$ n: i  二连赢的概率是25%, s6 S# \7 w; U- _1 I0 A
  三连赢的概率是12.5%) U/ l5 S1 m: T' F8 Y
  四连赢的概率是6.25%
: [% k$ k. ~) V' N; P) X  ……
& H6 o! ^4 o, |7 ]' n9 C! F9 _7 ^  十连赢的概率是0.09765625%
' }* z! I; n. f  {  这些概率值是所谓的相对概率,也就是二连赢25%的意思是只连续抛硬币4次之后,会有四种结果,二连赢就是其中的1种,所以他的概率是25%,同样的十连赢的概率也是基于1024次的10次抛硬币的结果组成。3 L( b+ b; {/ D& H7 B* _% {
  百家乐的真实概率含义是:
, ~8 D6 B7 Y' D! ]4 h7 h* U9 H2 R  假定一个口袋里有很多个球,其中有1号,2号,3号,4号,5号,6号,7号,8号,9号,10号球6 q1 x0 z" P. T2 S9 [: {8 u
  1号球有512个,2号256个,3号128个,4号64个,5号32个,6号16个,7号8个,8号4个,9号2个,10号1个。- V& z5 o0 z; D2 X9 k
  你要做的就是在这么多球里面每次摸一个球,然后放回去,再重新摸。如果你第一次摸到10号球,第一次一样也可以再摸到10次。
- q6 l* A) T! x( _& l  你每一次摸到的任何一个球的概率都是存在的,除非你摸无限次,才能接近之前提到的概率。概率在个体和短期内是无效的。
; \9 ^7 t& V1 e$ Z4 ?7 ?* y7 a( p  另外一个说法是,
% X) g: H) B$ i) R$ O  1、百家乐不是每次摸一个球,然后放回去,再重新摸,而是每次摸一个球,不放回去,再剩下的球里重新摸。
1 c; u' p! o  d8 D  2、概率在个体和短期内是有效的,牌入盒后出闲的概率是:49.32%,但是随着发出的牌的变化,牌盒内所剩下的牌数量的减少,他的概率就会每时每刻都会变化。
/ o6 p! k+ `4 c+ A1 d6 W  再把这个概率代入期望值公式,当+EV出现就下注,就会做到平均赢。) H; `1 ?$ l3 ~& N0 f" S
  平均赢只是长期而言会赢,短期也可能会被震幅消灭,这时就要算标准差,再接合你获得的优势,按凯利值下注就可以做到破产风险最低,利润最大化。9 ^: O* I, z" h  M- @; A
  对于这样的说法,百家乐玩家的解释是,首先,百家乐肯定是每次摸一球个放进去,只是袋子里的球和你的数学模型一定要配合。
* F6 k1 M' O- W/ Q$ J' T. A6 h  举个例子,如果你是打庄闲的,袋子里永远只有两个球,每次摸完一个之后要放回去,然后再摸。这个概念是不容置疑的。
. f" w7 r7 z. Y1 W  第二,因为大数法则和算牌对百家乐的无效性,牌盒内所剩下多少牌,对庄闲的比例不会发生任何的变化% Q: ~8 k, ]2 h7 K
  第三,凯利公式的问题在于:形而上学。* G: ~3 R/ u% k3 m* m$ c2 s/ x
  首先主观假设了一个不成立的底部,玩久了一定会遇到被爆仓的概念,当然任何一种模型都会有爆仓的可能,只是单纯的凯利更容易爆仓而已。研究的方向是多维+赢进补偿,玩过Diablo3就知道在Mp8的难度下,打到钥匙的可能性是80%。
: ^. c% [/ @8 k0 b' b% j  事实上,你玩的时候,基本上每次都能打到。
( U3 |$ V7 u' V' ^  因此,百家乐连赢概率和连赢策略,对于不同的玩家有不同的理解,如何找到适合于自己的玩法和制胜之道,是每个玩家都需要积累实战经验去摸索的。
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2#
多谢小超人的分享
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3#
感谢楼主分享你的心得体会
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